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  1. #1
    Really is Llama Not_A_Llama's Avatar
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    Quote Originally Posted by Tim K View Post
    Was down at the PD match on Saturday and got to thinking about this, so I did the math.

    BD = Bullet Drop
    A = Angle rifle is canted from vertical
    E = error, left or right

    E = BD tan A

    Example:
    At 425 yards, my .308 drops 31" with a 100 yard zero. If my rifle is canted 5° from vertical, the windage error is:

    E = 31" X tan 5°

    E = 31" X 0.0875

    E = 2.71"

    Here's another example because 5° is a lot and 425 yards isn't.

    Same rifle at 1,000 yards, bullet drop is 321". Assume cant of only 2°, which seems more realistic.

    E = 321 tan 2°

    E = 11.2"
    With your way of viewing things, I think you're actually looking for the Sine, not the tangent - consider the behavior of tangent at 45 degrees.

    There's actually more calculations that go in, and there's a reference point problem - it's a cool problem, I'm writing more up. My basic contention of there being a problem is that the way you're modeling it basically looks like 1) sight in 2) fire 3) rotate 4) fire 5) measure difference, while the more "accurate" behavior looks like 1) sight in 2) fire 3) rotate 4) sight in whilst canted 5) fire 6) measure.
    9mm - because they don't make a 9.1mm

  2. #2
    Woodsmith with "Mod-like" Powers
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    Quote Originally Posted by Not_A_Llama View Post
    With your way of viewing things, I think you're actually looking for the Sine, not the tangent - consider the behavior of tangent at 45 degrees.

    There's actually more calculations that go in, and there's a reference point problem - it's a cool problem, I'm writing more up. My basic contention of there being a problem is that the way you're modeling it basically looks like 1) sight in 2) fire 3) rotate 4) fire 5) measure difference, while the more "accurate" behavior looks like 1) sight in 2) fire 3) rotate 4) sight in whilst canted 5) fire 6) measure.


    Run the numbers, sine and tangent are essentially equal at small angles. Doesn't matter which one you use. It's true there's more to it. For instance, it's more properly calculated using the max ordinate, not the drop based on a 100 yard zero. I get it. I just don't care. The intended point of my post is not to calculate it with utmost precision but to illustrate that avoiding a canted rifle is important for precision distance shooting.
    "It takes considerable knowledge just to realize the extent of your ignorance"

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  3. #3
    Really is Llama Not_A_Llama's Avatar
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    It's not meant as a slight. I just thought it was odd you reached for the kinda-off function that's just as hard to calculate.
    9mm - because they don't make a 9.1mm

  4. #4
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    42

  5. #5
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    Quote Originally Posted by Byte Stryke View Post
    42
    Answer is: 0.9004(approx)

    Dave

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